A sector of circle of radius 9 cm has central angle of 120.It is rolled up so that the two bounding radii are joined together to form a cone.F
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area of sector=angle/360×πr^2
=120/360×22/7×9×9
=1/3×22/7×9×9
=22/7×3×9
=3.14×27
=84.78
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