Question

A sedan car of mass 200kg is moving with a certain velocity . It is brought to rest by the application of brakes, within a distance of 20m when the average resistance being offered to it is 500N.What was the velocity of the motor car?​

Answer 1

Answer

3.9/5

18

Explanation:

F=ma

500=200*a

a=2.5

now

v^2=u^2 +2as

0=u^2-2*2.5*20

u^2=100

u=10m/s

Answer 2

Answer:

The velocity of the car is 10 m/s.

Explanation:

Given:

• Mass (m) = 200 kg
• Distance (s) = 20 m
• Force (f) = 500 N

To find:

Velocity of the motor car.

Solution:

By Newton's second law,

F = m*a

where

• F = Force
• m = mass
• a = acceleration

So, a = F/m

Now we will find acceleration using this formula.

a = –500/200

⟹ a = – 2.5 m/s²

Now we have to find velocity of the motor.

• Final velocity (v) = 0
• Distance (s) = 20 m
• Acceleration (a) = – 2.5 m/s²

As we know that,

v² = u² + 2as

Now substitute the values

⟹ 0² = u² + 2 × – 2.5 × 20

⟹ u² = 10 m/s.