A see-saw 8m long is balanced in the middle. Two children of mass 30kg and 40kg are sitting on the same side of fulcrum at a distance of 1.5m and 3.5m .Where must a lady weighing 60kgf sit from fulcrum so as to balance the see- saw
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l=8m
m1=30
m2=40
m3=60
x1=1.5
x2=3.5
let the fulcrum lie at the centre (it has to lie there...LOL)
let the lady sit at a dis y from fulcrum
therefore by conserving net angular momentum
30*10*1.5+40*10*3.5-60*10*y=0
(we multiplied the masses with 10 so as to get weight)
300*1.5+400*3.5=600y
6y=4.5+14
y=18.5/6
y=3.08
therefore the lady should sit at a distance of 3.08 from the fulcrum (the fulcrum at the centre LOL) on the opposite side.
hope this helps
Anonymous:
lv him
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