a see-saw of length 4 m is supported at its centre. a boy we weighing 4 n sits at a distance of 1 m from centre of the see-saw. where should a girl weighing 2 n sit (on the other side of the see-saw so as to balance the weight of the boy.
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By using the principle of moments
Sum of anticlockwise monent= sum of clockwise monent
4*1=2*x
x = 4/2
x= 2 m
khush81:
ok
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