Physics, asked by bhargavi392, 2 months ago

A seesaw of length 4m is supported at its centre. A boy weighing 4N sits at a distance of 1m from the centre of the see-saw. Where should a girl weighing 2N sit on the other side of see-saw so as to balance the weight of the boy?
4m
6m
2m
16m​

Answers

Answered by chaubeysanjay1975
11

Answer:

2 miter

We know that according to the principle of lever, load x load arm effort x effort arm

4Nx 1m = 2 N x effort arm

Thus, effort arm = 2 m

Hence, a girl must sit at a distance of 2 metre so that the see-saw will get balanced.

Answered by soumyadeephalder07
0

Answer:

1.2m

Explanation:

Length of the see saw= 4m

Weight of the boy= 4N

Weight of the girl= 2N

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