Question

A segment AB of 2m length is divided at c into two parts such that AC2=AB*CB. find the length of CB

Answer 1

Answer:

Step-by-step explanation:

AC2 = AB X BC

(AB - CB)2 = AB X CB

(2 - CB)2 = 2 x CB

4 - 4CB +CB2 = 2CB

CB2 - 6CB + 4 = 0

CB = 6+ root(36-16)/2 or 6 -root(36 -16)/2

on solving we get

CB = 3 + root 5 or 3 - root 5

CB = 3 + root5 = 3+2.24 = 5.24m, which is not possible as AB = 2m

CB = 3- root5 = 3-2.24 = 0.76m.

Hope it's correct..

❤

Answer 2

Answer:

Step-by-step explanation:

See attachment