Question

A segment has endpoints at (3,−4) and (3,−17). How many units long is the segment?

Answer 1

Formula to be applied : -

$\mathsf{\underline{Distance\:Formula}: - }\\\\\boxed{\mathsf{Distance = \sqrt{(x_{2}-x_{1})^2 + (y_{2} -y_{1})^2}}}$

In the question, assume

x₁ = 3 , y₁ = - 4 , x₂ = 3 , y₂ = - 17

Applying distance formula

$\implies Distance = \sqrt{\{3-3\}^2+\{-17-(-4)\}^2}\\\\\implies Distance = \sqrt{(-17+4)^2}\\\\\implies Distance = \sqrt{(-13)^2}\\\\\implies Distance = 13 \quad Or \quad- 13 units$

But distance cannot be negative, so Distance = 13 units

Therefore, distance between the segment having end points as ( 3 , - 4 ) and ( 3 ,- 17 ) is 13 units.

Answer 2

Answer:

13

Step-by-step explanation: