Question

A self-fertilizing trihybrid plant forms 223) (1)8 different gametes and 64 different zygotes (2)4 different gametes and 16 different zygotes (3)8 different gametes and 16 different zygotes (4)8 different gametes and 32 different zygotes

Answer 1

Answer:

A self-fertilising trihybrid plant will have, n = 3.

The number of combinations of gametes = 2n. That is equal to 23 = 8 combinations.

With one row or column for each allele combination, the total number of boxes in a Punnett Square equals the number of rows times the number of columns. Multi-trait Punnett squares are large. A three trait square has 64 boxes. A four trait square will thus have 256 boxes.

So, the correct answer is option 1

Answer 2

Answer:

A self-fertilizing trihybrid plant forms 223)

(1)8 different gametes and 64 different zygotes ✔✔✔

(2)4 different gametes and 16 different zygotes (3)8 different gametes and 16 different zygotes (4)8 different gametes and 32 different zygotes