Question

A seller bought 2750 mangoes and 1210 apples at the same price.He sells in such a way that he can buy 406 mangoes with the sale of 322 mangoes and he can buy only 289 apples with the sale of 391 apples.the what is the overall profit percentage made by him?
A)0%
B)2%
C)5%
D)6%
E)10%

hi guys help me​

Answer 1

Answer:

Option A

Step-by-step explanation:

Cost of 2750 Mangoes = 1210 Apples

Total cost = 2420 Apples

Given: 406 = 322(100+x/100)

x = 6/23%

Given: 289 = 391(100+y/100)

y = 6/23% loss

Overall profit:

2750 Mangoes*(100+6/23/100) +1210 Apples*(100-6/23/100) = 2420*Apples (100+P/100)

1210 Apples*(100+6/23/100) +1210 Apples*(100-6/23/100) = 2420*Apples (100+P/100)

P = 0%

Answer 2

Given : A seller bought 2750 mangoes and 1210 apples at the same price

To find : overall profit

Explanation:

cost of the 2750 mangoes = cost of 1210 apples

therefore ,

total cost = 2420 apples

according to the question

406 mangoes with the sale of 322 mangoes

$406 = 322 (100+\frac{x}{100}) \\\\x = \frac{6}{23}$

also ,

289 apples with the sale of 391 apples

$289 = 391 (100+ \frac{y}{100})$

y = 6/23 % loss

thus ,

The overall profit  is

$2750 \times (100+\frac{6}{23\times 100})+1210\times (100-\frac{6}{23\times 100})= 2420 \times (100 + \frac{P}{100})\\\\1210 \times (100+\frac{6}{23\times 100})+1210\times (100-\frac{6}{23\times 100})=2420 \times (100 + \frac{P}{100})$

i.e

P = 0%

option (A)

there is no profit at all

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