Question

A seller mixed the low-quality pulse A of 10 Rs Per Kg with the good quality pulse B of rate 25 Rs. Per Kg. He is selling the mixture of the pulse at 15 Rs
Per Kg. In what ratio he had mixed the pulses A and B?​

Answer 1

Answer:

The ratio is 2:1

Step-by-step explanation:

Consider the amount of pulse A of price Rs. 10 = x

And the amount of pulse B of price Rs. 25 = y

Then the total amount of mixture = 10x + 25y

But the price per kg of mixture is Rs. 15

So, Total price of (x+y)kg = 15(x+y)

According to the equation,

15(x+y)=10x+25y

15x+15y=10x+25y

5x=10y

$\frac{x}{y}$ = $\frac{10}{5}$

$\frac{x}{y}$ = $\frac{2}{1}$

Hence, required ratio is 2:1.

#SPJ2

Answer 2

Answer:

Step-by-step explanation:

Answer:

The ratio is 2:1

Step-by-step explanation:

Consider the amount of pulse A of price Rs. 10 = x

And the amount of pulse B of price Rs. 25 = y

Then the total amount of mixture = 10x + 25y

But the price per kg of mixture is Rs. 15

So, Total price of (x+y)kg = 15(x+y)

According to the equation,

15(x+y)=10x+25y

15x+15y=10x+25y

5x=10y

=

=

Hence, required ratio is 2:1.