Math, asked by rajmalavika298, 7 months ago

A sells his goods 10% cheaper than B and B sells 10% cheaper than C;
how much percent are C's rates lower than A's?​

Answers

Answered by supergamer50
2

bro 20 percent is the answer

Answered by Anonymous
0

Given,

A sells 10% cheaper than B.

B sells 10% cheaper than C.

To find,

The percentage difference of A and C.

Solution,

Let, the selling price of the C = Rs. x

(Assume, x as a variable to do the further mathematical calculations.)

Selling price of B = x - (x ×10/100) = x - x/10 = Rs. 9x/10

Selling price of A = 9x/10 - (9x/10 × 10/100) = 9x/10 - 9x/100 = 90x-9x/100 = Rs. 81x/100

Price difference = x - 81x/100 = 100x-81x/100 = Rs. 19x/100

Percentage difference = 100 × (19x/100 ÷ x) = 100 × (19x/100 × 1/x) = 100 × (19/100) = 19%

(Here, the percentage is calculated by assuming the selling price of C as the reference value because selling price of C is greater than the selling price of A.)

Hence, the percentage difference will be 19%.

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