Question

A sells his goods 20% cheaper than B and 20% dearer than C. How much percentage is C‟s

goods cheaper / dearer than B​

Answer 1

Let tha selling price of B be 100 rupees

=>Then the selling price of goods by A =80 rupees

=>Now, 120% of selling price of goods by C = 80

=>Selling price of goods by C =

$\frac{100}{120} \times 80 = 66.67$

=> So C goods are cheaper than B goods by

$\frac{33.33}{100} \times 100\% = 33.3\%$

Answer is 33.3%

Answer 2

Step-by-step explanation:

Let tha selling price of B be 100 rupees

=>Then the selling price of goods by A =80 rupees

=>Now, 120% of selling price of goods by C = 80

=>Selling price of goods by C =

\frac{100}{120} \times 80 = 66.67

120

100

×80=66.67

=> So C goods are cheaper than B goods by

\frac{33.33}{100} \times 100\% = 33.3\%

100

33.33 ×100%=33.3%

Answer is 33.3%

hope it helps you ✌️