a semi circular part was removed from a rectangular field as shown in the figure. what is the new perimeter of the field
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Himanshu2084:
bhaii thanks jaroor krna mere answer ko
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the new perimeter will be 45 m because when we subtract 8 cm from rectangles breadth we get 3cm
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I hope this will help you.
circumference of semicircle =πr
8=diameter then 4=radius
circumference of semicircle is 22*4/7 =3.14*4 =12.56
perimeter of new rectangle = 52-8+12.56 = 56.56
circumference of semicircle =πr
8=diameter then 4=radius
circumference of semicircle is 22*4/7 =3.14*4 =12.56
perimeter of new rectangle = 52-8+12.56 = 56.56
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