A semi-circular sheet of metal of diameter 28cm is bent to form an open conical cup.Find the capacity of the cup.
Class: IX
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let the radius= 14cm
diameter of the circle sheet =28cm
circumference of semicircle sheet= 14 πcm
slant height of conical cup=l
circumference of the base of conical cup = circumference of semi circle sheet
2πR= πr
R=πr/2π=r/2
=14/2
=7cm
death of conical cup= height of cone
√l^2-r^2
√(14)2-(7)2
√196-49
√147
7√3 cm
capacity of the conical cap=1/3πR^2h
1/3*22/7*7^2*7√3
1078√3/3cm^3
622.383cm^3
the capacity of the conical is 622.383cm^3
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