Physics, asked by govindnautiyal04, 1 month ago

A semi-elliptical spring of length 500 mm, thickness 10 mm, and 40 mm broad is subjected to a load of 5 kN and get straightened. If the stress in spring should not cross 250 MPa, then calculate the number of plates, the initial radius of curvature, and central deflection. Take E as 200 GPa.​

Answers

Answered by royalpiano637
0

Answer: The primary function of a spring is to deflect or distort under load and to recover its original

shape when the load is released. During deflection or distortion, it absorbs energy and

release the same as and when required. Springs are used in many engineering applications

such as automobiles and railway buffers in order to cushion, absorb or control energy due to

shock and vibrations. Springs will suffer a sizeable change in form without being distorted

permanently when the loads are applied. Springs are generally classified as leaf springs or

helical springs. Leaf springs consist of a number of thin curved plates, each of same

thiclcness and width but of different lengths, all bent to the same curvature. Helical springs

are formed by coiling thick spring wire into a helix. Helical springs are classified into two

groups. When the helix angle is less than about lo", it is named as close-coiled helical

spring. In such springs, the wire experiences too little bending or direct shear stress and their

effect is neglected. Torsional stresses are predominant in such springs. If, however the helix

angle is significant, then the wire experiences both torsional and bending stresses. Such type

of spring is termed as open-coiled helical spring.  

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