Physics, asked by hameyafeme, 1 year ago

a semi infinite wire of uniform linear charge density is placed as shown in figure.The conical surface is of radius R and height h. the electric flux through curved surface of the cone is

correct option is \sqrt{2} lamda/ 3 e₀

Attachments:

MidA: is your option correct ??
MidA: I am getting "(lambda × R)/2€."
hameyafeme: It is correct option... Then also you send your solution
hameyafeme: BTW thanks
MidA: let someone else to try .
MidA: he/she may be able to give you correct solution
MidA: BTW flux should depend on radius also.
hameyafeme: Anyone with the answer?
AoKoSoHoAoT: Answer is Lamda×R/2€
Harshita1508deep: Answer is Lamda×R/2€ but how???

Answers

Answered by sarthaksaumya13
19

Answer:

λR/2ε

Explanation:

Integration of λ/4πεx * 2πxdx (limit o to R) and you get the answer.

Here, we have used formula of electric field of semi infinite wire at distance x=xλ/4πε and area of elemental ring=2πxdx

solving we get φ=λR/2ε

Please mark it as brainliest.

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