Physics, asked by hameyafeme, 11 months ago

a semi infinite wire of uniform linear charge density is placed as shown in figure.The conical surface is of radius R and height h. the electric flux through curved surface of the cone is

correct option is $\sqrt{2}$ lamda/ 3 e₀

Attachments:

MidA: is your option correct ??

MidA: I am getting "(lambda × R)/2€."

hameyafeme: It is correct option... Then also you send your solution

hameyafeme: BTW thanks

MidA: let someone else to try .

MidA: he/she may be able to give you correct solution

MidA: BTW flux should depend on radius also.

hameyafeme: Anyone with the answer?

AoKoSoHoAoT: Answer is Lamda×R/2€

Harshita1508deep: Answer is Lamda×R/2€ but how???

Answers

Answered by sarthaksaumya13

Answer:

λR/2ε

Explanation:

Integration of λ/4πεx * 2πxdx (limit o to R) and you get the answer.

Here, we have used formula of electric field of semi infinite wire at distance x=xλ/4πε and area of elemental ring=2πxdx

solving we get φ=λR/2ε

Please mark it as brainliest.

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