Question

A semicircle CD is mounted on a parallelogram ABCE as shown in the figure ifAB= 24 CM AE=13cm and EF=12cm find the perimeter and area of the given figure

Answer 1

• let the length of af=x cm
• then
• according to pythogous theorem
• ae^2=ef^2+af^2
• therefore,
• af^2=169-144
• therefore, af^2=25
• than af= 5 cms
• therefore fb=ab-af
• 24-5
• 19 cms
• fb=ec=19 cms
• therefore perimeter of arc ced=pi*d/2
• 3.14*19/2
• =29.83 cms
• therefore peeimeter of the figure =13+24+13+29.83
• =79.83 cms

sorry for spelling mistakes

i think so it is correct...