Math, asked by GiNgErBrEaDCoOkiE, 10 months ago

A semicircle is attached to the side of a rectangle as shown.

What is the best approximation for the area of this figure?

Use 3.14 to approximate pi.

Select from the drop-down menu to correctly complete the statement.

The area is
m².

Attachments:

Answers

Answered by soumya2301
44
\huge {\bf{\red{\fbox{\underline {Hey \: Mate }}}}}

\huge {SOLUTION }

Area of the given figure = Area of rectangle + Area of semi circle .

=> Area of rectangle = lb

=> Area of rectangle = 2× 6

=> Area of rectangle = 12 cm^2

Now,

=> Area of semi - circle

 = 1 \div 2\pi {r}^{2}

= 1/2 × 3.14 × 1.5 × 1.5

= 3.53cm^2

NOW ,

AREA OF THE GIVEN FIGURE = 12 + 3.53

= 15.53 cm^2

\huge{ANSWER}

The area of the given figure is 15.53 cm^2 .

jacekylie1: Hi, I think try to correct a mistake, u used the diameter of the semi circle as your radius
sagarmankoti: Hello! The units are in m and you have taken in cm. Please correct it if you can. Thank You!
chandansing77: hlo
chandansing77: hlo ji
Answered by jacekylie1
37

Answer:

15.53cm^2

Step-by-step explanation:

The area of a rectangle is given as A=lb, and that of a semi-circle is given as A=(πr^2)/2

So, the area of the whole figure is A=lb + (πr^2)/2

A=6×2 + (3.14×1.5^2)/2

A=12+(7.0650)/2

A=12+3.5325

A=15.53cm^2

HOPE THAT WAS HELPFUL.


ashish47110: by hand solve
sagarmankoti: Hello! The units are in m and you have taken in cm. Please correct it if you can. Thank You!
Similar questions