Question

a semicircle is described on the diagonal of a square of 14 cm as the diameter find area of the semicircle not included in the square​

Answer 1

Answer:

Step-by-step explanation:

Let us first take out the length of the square. As we know square has all its sides equal.

So by Pythagoras theorem,

(diagonal)^2=2*(side)^2

(14√2)^2=2x^2

392=2x^2

196=x^2

√196=x

14=x=side.

As circle is inscribed inside the square, it's diameter is equal to square's side.

And radius =1/2 diameter

Radius =1/2*14=7

Area=πr^2=22/7*7*7=22*7=154