A semicircle is drawn on AC. Two chords AB and BC of length 8 cm and 6 cm respectively are drawn in the semicircle. What is the measure of the diameter of the circle?
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1
Answer:
11 cm .
Step-by-step explanation:
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Since the point B lies on the circumference of the semicircle,
Pythogoras theorem:-
AB²+BC²=AC²
=> 8²+ 6²=AC²
=> 64+36=AC²
=> AC²=100
=> AC = √100
=> AC=10cm
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