Math, asked by Anonymous, 5 months ago

A semicircle is drawn on each side of a square, as shown. The square has sides of length
2
π
.



What is the area of the resulting shape?

Answers

Answered by dualadmire
8

Given:

Length of each side of the square= 2π

To find:

Area of the resulting shape.

Solution:

Area of square =

 {side}^{2}

Therefore, area of square =

( {2\pi})^{2}

 = 4 {\pi}^{2}

Diameter of semi circle = 2π

Radius of semi circle = π

Area of semi circle= \frac{\pi r^{2} }{2}

Here r= π

Area of 4 semi circles

= 2\pi  {r}^{2}

= 2\pi {\pi}^{2}

= 2 {\pi}^{3}

Total area of the resulting shape= area of square + area of 4 semi circles

4 {\pi}^{2}  + 2 {\pi}^{3}

Therefore the area of the resulting shape is 2\pi ^{2} (2+\pi ) square units.

Answered by amitnrw
5

Given :  A semicircle is drawn on each side of a square

The square has sides of length 2π

To Find : area of the resulting shape

Solution:

Side of square =  2π

Area of Square = (2π )² = 4π²

Side of Square = Diameter of semicircle = 2π

=> Radius =  2π /2 = π

Area of Semicircle = (1/2)πr²

= (1/2)ππ²

= (1/2)π³

area of 4 Semicircles  = 4 ( (1/2)π³)  = 2π³

area of the resulting shape = 2π³ +  4π²

= 2π²(π + 2)

2π²(π + 2) sq units is the area of resulting shape

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