Question

A semicircular disc of radius r is removed from a rectangular plate of sides r and 2r. calculate the C.M of remaining portion with respect to origin.

Answer 1

POSITION OF COM OF TWO PARTICLESCentre of mass of two particles of mass m1and m2separated by a distancer lies in between the two particles. The distance of centre of mass from any ofthe particle (r) is inversely proportional to the mass of the particle (m)i.e.r1mor1221rmrmorm1r1= m2r2orr1=221mmmr and r2=112mmmrHere,r1= distance or COM from m1andr2= distance or COM from m2From the above discussion, we see thatr1= r2=12if m1= m2, i.e., COM liesmidway between the two particles ofequal masses.Similarly, r1> r2if m1< m2and r1< r2if m2< m1, i.e., COM is nearer to theparticle having larger mass.Illustration :Two particles of mass 1 kg and 2 kg are located at x = 0 and x = 3 m. Findthe position of their centre of mass.Sol.Since, both the particles lies on x-axis, the COM will also lie on x-axis.Let the COM is located at x = x, thenr1= distance of COM from the particle of mass 1 kg= x please put brainly question and also put thanks