A semicircular portion of radius 7cm is cut out from a square paper of side 14cm. The perimeter of the remaining paper is?
Answers
Answer:
Perimeter of remaining part is 64cm
Step-by-step explanation:
The perimeter of square = Side + Side + Side + Circumference of cut out
The circumference of semicircle = 2πr/2 = 43.98/2 = 44/2 = 22cm
Perimeter of remaining paper = 14 + 14 + 14 + 22 = 64 cm
The perimeter of the remaining paper is 64 cm if A semicircular portion of radius 7cm is cut out from a square paper of side 14cm
Given : A semicircular portion of radius 7cm is cut out from a square paper of side 14cm.
To Find : perimeter of the remaining paper
Solution:
Perimeter of Square = 4 * side
side = 14 cm
Hence Perimeter = 4 * 14 = 56 cm
A semicircular portion of radius 7cm is cut out
=> Diameter = 2 * radius = 2 * 7 = 14 cm
New perimeter = Perimeter of Square - Diameter + circumference of semicircle
Circumference of a circle = 2π(radius)
Circumference of a semi circle = (1/2) 2π(radius) = π * radius
radius = 7 cm
π = 22/7 cm
Circumference of the semicircle = (22/7) * 7 = 22 cm
New perimeter = 56 - 14 + 22
= 64 cm
The perimeter of the remaining paper is 64 cm
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