Question

A semicircular region circumscribes a circle which symmetrically fits into it. If a dice is rolled inside the semicircular part only what is the probability that the dice will fall in the circular region



please don't give useless answer it is urgent ​

Answer 1

Answer:

Radius of semi - circular piece =14 cm

Circumference of semi - circle = πr=722×14

=44 cm

∴ Circumference of base of cone =44 cm

⇒2πR=44cm⇒R=2×2244×7=7cm

Radius of semi - circular sheet = slant height of conical cup ⇒l=14cm

Now, R2+h2=l2⇒72+h2=142⇒h=196−49=147=73cm

∴ Capacity of cup =31πR2h=31×722×7×7×73=622.3cm3

Answer 2

$\star\:\:\:\bf\large\underline\blue{Question:-}$

• A semicircular region circumscribes a circle which symmetrically fits into it. If a dice is rolled inside the semicircular part only what is the probability that the dice will fall in the circular region.

$\star\:\:\:\bf\large\underline\blue{Solution:-}$

Since, the dice is rolled inside the Semicircular part only, then it must fall in the circular region.

So,

$P(E) =1$

$\star\:\:\:\bf\large\underline\blue{Answer:-}$

• Probability of the given event is 1.