A semicircular sheet of diameter 28 cm is bent to form an open conical cup. Find the capacity of the cup. (Use root3 = 1.732.)
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Secondary School Math 8 points
A semicircular sheet of paper of diameter 28 cm is bent into an open conical cup. find the depth and the capacity of the cup
Ask for details Follow Report by I5shinghashstejugga 14.12.2016
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Solution:-
Slant height of the conical cup, 'l' = radius of the semi-circular sheet, R = 14 cm
Let radius and height of the conical cup be 'r' and 'h' respectively.
Circumference of the base of the cone = Length of arc of the semi-circle
Or, 2πr = (1/2)2πR
Or, 2πr = (1/2)(2π)(14)
Or, r = 7 cm
Now, we know that l² = h² + r²
(14)² = (h)² + (7)²
h² = 196 - 49
h = √147
Height or depth of the conical cup = 12.124 cm
Now, capacity of the conical cup = 1/3πr²h
= 1/3*22/7*7*7*12.124
= 13069.672/21
Capacity of the conical cup = 622.365 cu cm
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