Math, asked by unnati4638, 11 months ago


A semicircular sheet of diameter 28 cm is bent to form an open conical cup. Find the capacity of the cup. (Use root3 = 1.732.)​

Answers

Answered by Arpitmaurya123bdh
2

Brainly.in

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Secondary School Math 8 points

A semicircular sheet of paper of diameter 28 cm is bent into an open conical cup. find the depth and the capacity of the cup

Ask for details Follow Report by I5shinghashstejugga 14.12.2016

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Golda

Golda Ace

Solution:-

Slant height of the conical cup, 'l' = radius of the semi-circular sheet, R = 14 cm

Let radius and height of the conical cup be 'r' and 'h' respectively.

Circumference of the base of the cone = Length of arc of the semi-circle

Or, 2πr = (1/2)2πR

Or, 2πr = (1/2)(2π)(14)

Or, r = 7 cm

Now, we know that l² = h² + r²

(14)² = (h)² + (7)²

h² = 196 - 49

h = √147

Height or depth of the conical cup = 12.124 cm

Now, capacity of the conical cup = 1/3πr²h

= 1/3*22/7*7*7*12.124

= 13069.672/21

Capacity of the conical cup = 622.365 cu cm

Answer.

Answered by ayush1516
0

Answer:

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