Question

A semicircular sheet of metal of diameter 28 cm
is bent into an open conical cup. Find the depth
and capacity of cup (3=1.73) (HOTS)​

Answer 1

Answer:

Answer. Given diameter = 28 cm Radius, r = 14 cm Circumference of semi circle = πr = (22/7) x 14 = 44 cm This becomes circumference of base of cone 2πR = 44 R = 44 x (7/44) R = 7 cm The radius of semi circular sheet = slant height of conical cup That is l = 7 cm We know that r2 + h2 = l2 142 + h2 = 72 196 – 49 = h2 h2 = 147 Therefore, h = 7√3 cm That is depth of the conical cup is 7Ö3 cm Capacity of cup = (1/3) πr2h = (1/3) x (22/7) x 72 x 7√3 = 622.37 cu cm