Question

« A semicircular sheet of metal of diameter 28 em is rolled to form an open conical cup. Find the capacity of the cup
.​

Answer 1

Answer:

Don't know sorry bye

Step-by-step explanation:

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Answer 2

Step-by-step explanation:

As we know that the circumference of a circle is given as-

Circumference =πr

Whereas, r is the radius of circle

Diameter of circular sheet =28cm

∴ Radius of circular sheet =

2

28

=14cm

Therefore,

Circumference of circular sheet =14π

When a semi-circular sheet is bent to form an open conical cup, the radius of the sheet becomes the slant height of the cup and the circumference of the sheet becomes the circumference of the base of the cone.

Slant height of cup (l)= Radius of circular sheet =14cm

Circumference of the base of cone = circumference of circular sheet =14π

Let r be the radius of the base of cone

∴2πr=14

⇒r=7cm

Let h be the height of cup.

Therefore,

l

2

=r

2

+h

2

(14)

2

=(7)

2

+h

2

⇒h=

196−49

=

147

=7

2

cm

Now,

Capacity of cup = Volume of cone

As we know that, volume of cone is given as-

V=

3

1

πr

2

h

Therefore,

Capacity of cup =

3

1

×

7

22

×(7)

2

×7

3

=622.4cm

3

Thus the capacity of the cup is 622.4cm

3

.

Hence the correct answer is 622.4cm

3.

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