Question

A semicircular sheet of metal of diameter 28cm is bent into open conical cup find depth and capacity of cup

Answer 1

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Slant height of the conical cup

'l' = radius of the semi-circular sheet

R = 14 cm

Let radius "r" and height "h"

Circumference of the base of the cone = Length of arc of the semi-circle

Or, 2πr = (1/2)2πR

Or, 2πr = (1/2)(2π)(14)

Or, r = 7 cm

Now, we know that

l² = h² + r²

(14)² = (h)² + (7)²

h² = 196 - 49

h = √147

Height or depth of the conical cup = 12.124 cm

Now, capacity of the conical cup = 1/3πr²h

= 1/3×22/7×7×7×12.124

= 13069.672/21

Capacity of the conical cup = 622.365 cu cm

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