a semicircular sheet of paper of diameter 14 cm is bent to form a conical cup.find the capacity of the cup
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Answer:
Radius, r = 14 cm
Circumference of semi circle = πr
= (22/7) x 14 = 44 cm
This becomes circumference of base of cone
2πR = 44
R = 44 x (7/44)
R = 7 cm
The radius of semi circular sheet = slant height of conical cup
That is l = 7 cm
We know that r2 + h2 = l2
142 + h2 = 72
196 – 49 = h2
h2 = 147
Therefore, h = 7√3 cm
That is depth of the conical cup is 7Ö3 cm
Capacity of cup = (1/3) πr2h
= (1/3) x (22/7) x 72 x 7√3
= 622.37 cu cm
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