Question

a semicircular sheet of paper of diameter 28cm is bent into open conical Cup find the depth and capacity of the cup can anyone answer this by trying it out in a sheet of paper
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Answer 1

Answer:

Step-by-step explanation:

As you fold it the diameter of the semicircle will become the cone's base's circumference.

Radius of the semicircle will be cone's slant height

2πr=28

R=49/11

14^2 - (49/11)^2=H2

√196-2201/121

146•6/11

Height is 13.32