Question

. A semiconductor material with a band gap of 0.12 eV is exposed to photons of energy 0.4eV. Analyse the result?

Answer 1

I know the answer but follow

Answer 2

Given info : A semiconductor material with a band gap of 0.12 eV is exposed to photons of energy 0.4 eV.

we have to analyse the result.

explanation : before going to explain it, let's review “photoelectric effect,” according to this theory, when a ray of light (photons) strikes on the surface of metal/metalloids, and its incident energy is greater than work function/band gap, it ejects electrons from its surface.

mathematical equation is.. E - Φ = KE_{max}

from above explanation, it is clear that when energy of incident phtons is greater than band gap of semiconductor, it remove electrons from its surface. and due to movement of electrons, electrical energy is developed.

here given band gap = 0.12 eV < 0.4 eV = energy of photons so electron must be removed from its (semiconductor) surface. and electrical energy will be developed.