Question

A senior physics class conducting a research project on projectile motion constructs a device that can launch a cricket ball. The launching device is designed so that the ball can be launched at ground level with an initial velocity of 28 m/s at an angle of 30° to the horizontal. (g=9.8m/s2).i. Calculate the horizontal component of the velocity of the ball:(a) initially /1.5marks(b) after 2.0 s. /1.5 marks ii. Calculate the vertical component of the velocity of the ball:(a)initially /1.5marks(b) after 1.0 s/1.5marks .iii. At which point in its flight will the ball experience its minimum speed?/1markiv. (a) At what time after being launched will the ball hitto the ground? /1mark(b)Calculate the horizontal range of the ball./1markv. If the effects of air resistance were taken into account, which one of the following statements would be correct?/1mark(a)The ball would have travelled a greater horizontal distance before striking the ground.(b)The ball would have reached a greater maximum height.(c)The ball’s horizontal velocity would have been continually decreasing​

Answer 1

Answer:

the acceleration due to gravity is only 1.67 m/s2.

Answer 2

(a) 2.9 s.

(b) 37 m/s

(c) Horizontal range = 69 m.

(d) Maximum height = 6.5 m.