. A sequence an is defined by an = 5 – 2n. Prove that it is an AP.
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Step-by-step explanation:
an=5-2n
Let..a1=1
a2=2
a3=3
Substitute it...
a1=5-2(1)
= 3...... (1)
a2=5-2(2)
=1.............(2)
a3=5-2(3)
= - 1......(3)
Series =3,1,-1
From this we get common diffidence is - 2
Hence it is in AP
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