Question

A sequence consists of 60 terms, if first and last are 7 and 125 . What is the 32 term?

Answer 1

Step-by-step explanation:

a = 7

An = 125

a + (n-1)d = 125

7 + (60-1)d = 125

59d = 125-7 = 118

59d = 118

d = 2

A(32) = a + 31d

= 7 + 31(2)

= 7 + 62 = 69

Answer 2

Answer:

a32=69

Step-by-step explanation:

an=125

a60=7+59d

125=7+59d

118=59d

d=2

a32=7+31X2

    =7+62

    =69