A sequence is defined recursively by f(1)=16 and f(n)=f(n-1)+2n. Find f(4) 1) 32 2) 30 3) 28 4) 34
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2
f(4)=f(3)+8
f(3)=f(2)+6
f(2)=f(1)+4=16+4=20
f(3)=26
f(4)=34
f(3)=f(2)+6
f(2)=f(1)+4=16+4=20
f(3)=26
f(4)=34
Answered by
1
Putting n=2, f(2)=f(1)+2*2 => f(2)=20
n=3, f(3)=f(2)+2*3 => f(3)=26
n=4, f(4)=f(3)+2*4 => f(3)=34
n=3, f(3)=f(2)+2*3 => f(3)=26
n=4, f(4)=f(3)+2*4 => f(3)=34
HeenaN:
f(4)=34 i wrote f(3) again by mistake
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