Math, asked by savitampp1979, 5 months ago

A sequence is obtained by deleting all
perfect squares from a set of natural
numbers. Find the remainder when
the 2003rd term of the new sequence
is divided by 2048​

Answers

Answered by suchismitabag00
0

Step-by-step explanation:

tk cuckvivk, vvjvifucigkvkbobcjovlbkcudj kicu jcjdhnbbhhhj

Answered by parashs864
0

45 numbers in this sequence will be deleted.

2025-45=1980 terms.

we need 2003rd term in 2025+23=2048.

the remainder when 2048÷2048=0

Attachments:
Similar questions