A series circuit consists of r = 20 ω, l = 20 mh, and ac supply 60 v with f = 100 hz. the voltage drop across r is a
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The expression for impedance of series R - L circuit is Z = ( R^2 + 4.π^2f^2L^2)^1 / 2
Here,
R = 20 Ω, L = 20 mH, V = 60 V and f = 100 Hz
Z = [20^2 + 4 × 3.14^2 × 100 ^2 × (20 × 10^ - 3)^2]^1 / 2 = 23.61 Ω
Therefore, electric current through the circuit i.e both through resistor and inductor will be 60 / 23.61 = 2.54 A.
Here,
R = 20 Ω, L = 20 mH, V = 60 V and f = 100 Hz
Z = [20^2 + 4 × 3.14^2 × 100 ^2 × (20 × 10^ - 3)^2]^1 / 2 = 23.61 Ω
Therefore, electric current through the circuit i.e both through resistor and inductor will be 60 / 23.61 = 2.54 A.
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