Question

A series circuit has a 6 V battery connected to a 1 ohm resistor and a 2 ohm resistor. The voltage drop across the 2 ohm resistor is:
1) 4 V
2) 6 V
3) 2 V
4) 3 V

Answer 1

we know that V=IR here a.t.w V=6v and total resistsnce is 3ohm so put these in above equation 6=I×3
I=2
voltage drop across 2ohm resistance
V=IR
V=2×2
V=4v