Question

A series combination of three resistors takes a current of 2A from a 24V supply. If the resistances are in the ratio 1:2:3, find the value of unknown resistors.

Answer 1

Explanation:

(1+2+3)x =6x

as V=IR ,

put the values now,

24= 2×6x

24/12=X

X=2

so the resistor's value s are 2, 2×2=4 , 3×2 =6

Answer 2

Given :

Current through the resistors , I = 2 A .

Supply voltage , V = 24 V .

Ratio of resistances 1 : 2 : 3 .

To Find :

The value of unknown resistors.

Solution :

It is given that the ratio of resistances are 1 : 2 : 3 .

Let , resistance of smallest resistor is R .

Therefore , resistance of all three resistors are R , 2R and 3R .

So , equivalent resistance , $R_{net}=R+2R+3R=6R$

By , ohm's law :

$V=IR_{net}\\\\R_{net}=\dfrac{V}{I}\\\\6R=\dfrac{24\ V}{2\ A }\\\\R=2\ ohms$

Therefore , the value of resistances are 2 , 4 , 6 ohms .

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