Question

A series l c r circuit with R=44 C=8uf and L=50 h is connected to a variable frequency 220 ac supply caluculate angulat frequency Impidence and current at resonance condition

Answer 1

Answer:

Long sum

Explanation:

Answer 2

The angular frequency and the current is 50 Hz and 5 A respectively.

Explanation:

Given that,

Resistance of LCR circuit, R = 44 ohms

Capacitance, $C=8\ \mu F=8\times 10^{-6}\ F$

Inductance, $L=50\ H$

Voltage, f = 220 Hz

At resonance,

Inductive impedance = Capacitive impedance

$X_L=X_c\\\\\omega = \sqrt{\frac{1}{LC} }\\\\\omega = \sqrt{\frac{1}{50\times 8\times 10^{-6}} }\\\\\omega=50\ Hz$

Current I is given by :

$I=\dfrac{V}{R}\\\\I=\dfrac{220}{44}\\\\I=5\ A$

So, the angular frequency and the current is 50 Hz and 5 A respectively.

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