Question

A series LCR circuit has R = 2002, L = 663 mH and C = 26-5 uF. The applied
alternating voltage has an amplitude of 50 V and a frequency of 60 Hz so that
XL = 250 and Xc= 100 2. The peak current is​

Answer 1

Answer:

At resonance, the frequency of supply power equals to naturan frequency of LCR circuit.

Impedence, Z=

R

2

+(ωL−1/ωC)

ω

L

=

ω

C

1

so, Z=R

I=V/R=200/20=10 A

Power, W=V×I=200×10=2000 W