Question

a series LCR circuit is connected to an AC source whose frequency is less than the resonant frequency of the circuit. which one will you increase to improve the power factor of the circuit whether it is L or C justify

Answer 1

Answer:

in order to improve the power factor of the circuit we have to increase the value of inductance

Explanation:

As we know that angular frequency for which circuit is in resonance is given as

$\omega = \sqrt{\frac{1}{LC}}$

now we know that the given frequency is slightly less than the resonance frequency

So we have average power of the circuit is given as

$P = i_{rms} V_{rms} cos\phi$

so here power factor is given as

$F = cos\phi$

$F = \frac{R}{\sqrt{(x_c - x_l)^2 + R^2}}$

now in order to improve power factor we have to decrease the value of

$\sqrt{(x_c - x_l)^2 + R^2}$

so here we have to decrease the value of

$(x_c - x_l)$

so we have to increase the value of inductance "L"

#Learn

Topic : LCR circuit

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