) A series LCR circuit of an inductance of 4 H, a capacitance of 1µF and a resistance of 20 ohms is tuned to resonance by connecting it across a variable frequency AC supply . Calculate the ratio of the voltage across the inductance to that across the resistance.
Answers
Answer:
An RLC circuit is an electrical circuit consisting of a resistor (R), an inductor (L), and a capacitor (C), connected in series or in parallel. ... Introducing the resistor increases the decay of these oscillations, which is also known as damping. The resistor also reduces the peak resonant frequency.
Explanation:
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Answer:
SOLVED
Explanation:
Electrical resonance occurs in an AC circuit when the two reactances which are opposite and equal cancel each other out as XL = XC and the point on the graph at which this happens is were the two reactance curves cross each other. In a series resonant circuit, the resonant frequency, ƒr point can be calculated as follows.
xL = xc
2πfL = 1/2πfc
f² = 1/4π²Lc
f = 1/2π√Lc Hz , OR 1/√Lc rads
f = 1/2π × √10∧6/4 = 10³/4π = 79.6 HZ
Z = R
VL : VR = iL/iR = L/R = 2πFl/R = 2π×79.6×4÷20 = 100 : 1