Question

A series LR circuit is connected with AC source of maximum voltage 100V.if maximum voltage across inductor is 80 V,then effective current in the Circuit(resistance of the resistor is 15 ohm)​

Answer 1

Answer:

current in 1st one is I=v÷r=100÷15

current in inductor is I=V÷R=80÷15

Answer 2

Current flowing through the resistor is 1.33 A.

Given :

Maximum voltage source = 100 V.

Voltage across inductor = 80 V.

Resistance of resistor = 15 ohm.

It is also given that the LC circuit is in series .

Since, sum of voltage across resistance and inductor is equal to the source voltage.

Therefore, voltage across resistance is , $V_r=100-80=20 \ V$.

Now, according to ohm's law , $I=\dfrac{V}{R}$     ...... equation 1.

Putting value of V and R in above equation .

$I=\dfrac{20}{15}=1.33 \ A.$

Since, the circuit is in series therefore current through each element is same i.e 1.33 A.

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Alternating Current

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