Question

A series of lines in the spectrum of atomic hydrogen lies at wavelengths 656.46, 486.27, 434.17 and 410.29 nm. The of next line in this series is

Answer 1

Ask Questions, Get Answers

 

Questions  >>  JEEMAIN and NEET  >>  Chemistry  >>  Atomic Structure



Next similar question

Q)

 

A series of lines in the spectrum of atomic H lies at wavelengths 656.46 , 486.27 , 434.17 , 410.29 mm. what is the wavelength of next line in this series?

(a)493.3nm(b)397.2nm(c)593.4nm.(d)392.3nm(a)493.3nm(b)397.2nm(c)593.4nm.(d)392.3nm



A)

 

Need homework help? Click here.

The given series lies in the visible region and thus appears to be Balmer series

Given:

n1n1 = 2

λ=410.29×10−7λ=410.29×10−7 cm

n2=?n2=?

1λ1λ= RH[1n21−1n22]RH[1n12−1n22]

1410.29×10−71410.29×10−7= 109678[1n21−1n22]109678[1n12−1n22]

n2n2 = 6

Next line will be obtained during the jump of electron from 7th7th to 2nd2nd shell

1λ1λ= RH[122−172]RH[122−172]

= 109678[14−149]109678[14−149]

λ=397.2×10−7λ=397.2×10−7 cm

λ=397.2λ=397.2 nm