Math, asked by raushanraj3880, 8 months ago

A series of rectangles is drawn such that sum of the two sides (a+b) adds up to 2 cms.

A circle is drawn with a diameter of I cms (mean of the two sides of the rectangle). If

area of such a rectangle is denoted by A1 and area of the circle is denoted by A2, then,

(A) A1 > A2, when a=b= l but A1<A2as"a"becomes closetozeroand"b"close to 2.

(B) A1 is greater than A2, for all such rectangles

(C) A1is less than A2, for all such rectangles

(D) perimeler of any such rectangle is fixed and is smaller than the circumference of the circle

Answers

Answered by cnhemanthraj1977
3

Answer:

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