Question

A series R-L-C (R= 10 ohm, Xl = Xc = 20 ohm) circuit is supplied by V = 10Sinwt volt then power dissipation in circuit

Answer 1

The power dissipation in circuit is 5 W.

Explanation:

We know that,

Power dissipation, P =$(\dfrac{V}{\dsqrt{Z}} )^{2} \times R$

Given,

$X_{l} =X_{c}=20 \Omega$, Z = R = 10

∴ Power dissipation, P = $(\frac{10}{\sqrt{2} } )^{2} \times 10$

= 5 Watt

Hence, the power dissipation in circuit is 5 W.

Answer 2

The power dissipation in circuit is 5 watt.

Explanation:

Given that,

The voltage equation is

$V = 10\sin\omega t$

Resistance R = 10 ohm

Inductive reactance $X_{L}=20\ \Omega$

Capacitive reactance $X_{C}=20\ \Omega$

Peak voltage = 10 V

We need to calculate the power dissipation in circuit

Using formula of power dissipation

$P=(\dfrac{V_{rms}}{Z})^2\times R$

Here, $X_{L}=X_{C}$

So, Z = R

$P=\dfrac{(V_{rms})^2}{R}$

$P=\dfrac{\dfrac{(V_{p}}{\sqrt{2}})^2}{R}$

Put the value into the formula

$P=\dfrac{(\dfrac{10}{\sqrt{2}})^2}{10}$

$P=5\ Watt$

Hence, The power dissipation in circuit is 5 watt.

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Topic : power dissipated

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