Question

A servo voltage stabiliser restricts the voltage
output to 220 V ±1%. If an electric bulb rated at
220 V, 100 W is connected to it, what will be the
minimum and maximum power consumed by it?
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Answer 1

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Answer 2

Answer:

102W

Explanation:

Output voltage = 220 ± 1% 1% of 220V = 2.2v The resistance of bulb R = V2/P = (220)2/100 = 484Ω (a) For minimum power consumed V1 = 220 – 1% = 220 – 2.2 = 217.8 ∴ i = V1/R = 217.8/484 = 0.45A Power consumed = i × V1 = 0.45 × 217.8 = 98.01W (b) for maximum power consumed V2 = 220 + 1% = 220 + 2.2 = 222.2 ∴ i = V2/R = 222.2/484 = 0.459 Power consumed = i × V2 = 0.459 × 222.2 = 102