Question

A set A has 3 elements and another set has 6 elements . Then options: a)3≤n(AUB)≤6 b)3≤n(AUB)≤9 c)6≤n(AUB)≤9 d)0≤n(AUB)≤9​

Answer 1

Hi,

Here we can take two case that when A is subset of B and A is not subset of B case−1A⊂B So A ∪B = n(B)= 6 Now when A is not subset of B and all the elements of A and B are different then A∪B = 6+3 = 9 so C is the correct option