A set containing 6 element total number of proper subset is
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The number of sets of a set containing n-elements =2^n .
A proper subset of a set is the set whose elements are in the given set, but it is not equal to the set.
Let S be a subset of A, S is called Proper subset if and only if it is a subset of A, and S ≠ A .
So, The number of proper subsets of a set containing n-elements is
As, The number of subsets contains a improper subset that is the set itself, so 1 is subtracted from number of total subsets to get number of proper subsets.
A proper subset of a set is the set whose elements are in the given set, but it is not equal to the set.
Let S be a subset of A, S is called Proper subset if and only if it is a subset of A, and S ≠ A .
So, The number of proper subsets of a set containing n-elements is
As, The number of subsets contains a improper subset that is the set itself, so 1 is subtracted from number of total subsets to get number of proper subsets.
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1
Answer:
64
Step-by-step explanation:
Tip
- A set A is a subset of another set B if all elements of the set A are elements of the set B. In other words, the set A is contained inside the set B. The subset relationship is denoted as A⊂B
Given
A set containing 6 element
Find
total number of proper subset
Solution
Since the number of subsets of a set are
if the set contains n elements,
∴ Number of subsets =
Final Answer
64
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